Difference between revisions of "BCAL Beam Test Plots, November 20, 2006"
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* Gain Correction: | * Gain Correction: | ||
| − | *# Establish the '''means''' of each cell in the Monte Carlo and find the ratio wrt Cell 8 | + | *# Establish the '''means''' of each cell in the Monte Carlo and find the ratio wrt MC Cell 8 |
*# Find the current ratio of each ADC in the beamtest data wrt to North 8 | *# Find the current ratio of each ADC in the beamtest data wrt to North 8 | ||
*# Correct the ADC ratio to match the Monte Carlo Ratios | *# Correct the ADC ratio to match the Monte Carlo Ratios | ||
| − | *#*The ratio of Cell 8 to North 8 defines the MeV/Channel | + | *#*The ratio of MC Cell 8 to North 8 defines the MeV/Channel |
| + | [[Image:EnergyN7.gif|thumb|left|100px|North 7]] [[Image:EnergyN8.gif|thumb|left|100px|North 8]] [[Image:EnergyN9.gif|thumb|left|100px|North 9]] [[Image:EnergyN12.gif|thumb|left|100px| North 12]] | ||
| − | ; How does this look over the entire tagger spectrum? | + | : <math> \frac{MC 8}{North 8} = 0.018 \frac{MeV}{Channel}</math> |
| + | <br> | ||
| + | <br> | ||
| + | ; How does this look over the entire tagger spectrum? | ||
| + | [[Image:Energysum_1.gif]] | ||
| + | |||
| + | <br> | ||
| + | ; What if we look at MC 8 vs North 8 with Tagger Energy cuts? | ||
Revision as of 18:33, 17 November 2006
First go
- Gain Correction:
- Establish the means of each cell in the Monte Carlo and find the ratio wrt MC Cell 8
- Find the current ratio of each ADC in the beamtest data wrt to North 8
- Correct the ADC ratio to match the Monte Carlo Ratios
- The ratio of MC Cell 8 to North 8 defines the MeV/Channel
- How does this look over the entire tagger spectrum?
- What if we look at MC 8 vs North 8 with Tagger Energy cuts?
