Difference between revisions of "BCAL Beam Test Plots, November 20, 2006"

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; What if we look at MC 8 vs North 8 with Tagger Energy cuts?
 
; What if we look at MC 8 vs North 8 with Tagger Energy cuts?
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[[Image:AdcNn8fit 300to400unzoom.gif|thumb|left|100px|North9 300<Ephoton<400]]
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[[Image:Escih11fit 300to400.gif|thumb|none|100px|MC9 300<Ephoton<400]]
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: <math>  (\frac{MC 8}{North 8})_{300<Ephoton<400} = 0.0177 \frac{MeV}{Channel}</math>
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 +
 +
[[Image:AdcNn8fit 500to600unzoom.gif|thumb|left|100px|North9 500<Ephoton<600]]
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[[Image:Escih11fit 500to600.gif|thumb|none|100px|MC9 500<Ephoton<600]]
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: <math>  (\frac{MC 8}{North 8})_{500<Ephoton<600} = 0.0165 \frac{MeV}{Channel}</math>
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*'''Very Strange: Apparent Energy Dependence'''

Revision as of 18:52, 17 November 2006

First go

  • Gain Correction:
    1. Establish the means of each cell in the Monte Carlo and find the ratio wrt MC Cell 8
    2. Find the current ratio of each ADC in the beamtest data wrt to North 8
    3. Correct the ADC ratio to match the Monte Carlo Ratios
      • The ratio of MC Cell 8 to North 8 defines the MeV/Channel
North 7
North 8
North 9
North 12
{\frac {MC8}{North8}}=0.018{\frac {MeV}{Channel}}



How does this look over the entire tagger spectrum?

Energysum 1.gif


What if we look at MC 8 vs North 8 with Tagger Energy cuts?
North9 300<Ephoton<400
MC9 300<Ephoton<400
({\frac {MC8}{North8}})_{{300<Ephoton<400}}=0.0177{\frac {MeV}{Channel}}


North9 500<Ephoton<600
MC9 500<Ephoton<600
({\frac {MC8}{North8}})_{{500<Ephoton<600}}=0.0165{\frac {MeV}{Channel}}


  • Very Strange: Apparent Energy Dependence
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