Difference between revisions of "BCAL Beam Test Plots, November 20, 2006"
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*#*The ratio of MC Cell 8 to North 8 defines the MeV/Channel | *#*The ratio of MC Cell 8 to North 8 defines the MeV/Channel | ||
| − | [[Image:EnergyN7.gif|thumb|left|100px|North 7]] [[Image:EnergyN8.gif|thumb|left|100px|North 8]] [[Image:EnergyN9.gif|thumb|left|100px|North 9]] [[Image:EnergyN12.gif|thumb| | + | [[Image:EnergyN7.gif|thumb|left|100px|North 7]] [[Image:EnergyN8.gif|thumb|left|100px|North 8]] [[Image:EnergyN9.gif|thumb|left|100px|North 9]] [[Image:EnergyN12.gif|thumb|none|100px| North 12]] |
: <math> \frac{MC 8}{North 8} = 0.018 \frac{MeV}{Channel}</math> | : <math> \frac{MC 8}{North 8} = 0.018 \frac{MeV}{Channel}</math> | ||
| Line 13: | Line 13: | ||
<br> | <br> | ||
; How does this look over the entire tagger spectrum? | ; How does this look over the entire tagger spectrum? | ||
| − | [[Image:Energysum_1.gif]] | + | [[Image:Energysum_1.gif|480px]] |
<br> | <br> | ||
; What if we look at MC 8 vs North 8 with Tagger Energy cuts? | ; What if we look at MC 8 vs North 8 with Tagger Energy cuts? | ||
| − | [[Image:AdcNn8fit 300to400unzoom.gif|thumb|left|100px| | + | [[Image:AdcNn8fit 300to400unzoom.gif|thumb|left|100px|North8 300<Ephoton<400]] |
| − | [[Image:Escih11fit 300to400.gif|thumb|none|100px| | + | [[Image:Escih11fit 300to400.gif|thumb|none|100px|MC8 300<Ephoton<400]] |
: <math> (\frac{MC 8}{North 8})_{300<Ephoton<400} = 0.0177 \frac{MeV}{Channel}</math> | : <math> (\frac{MC 8}{North 8})_{300<Ephoton<400} = 0.0177 \frac{MeV}{Channel}</math> | ||
| − | [[Image:AdcNn8fit 500to600unzoom.gif|thumb|left|100px| | + | [[Image:AdcNn8fit 500to600unzoom.gif|thumb|left|100px|North8 500<Ephoton<600]] |
| − | [[Image:Escih11fit 500to600.gif|thumb|none|100px| | + | [[Image:Escih11fit 500to600.gif|thumb|none|100px|MC8 500<Ephoton<600]] |
: <math> (\frac{MC 8}{North 8})_{500<Ephoton<600} = 0.0165 \frac{MeV}{Channel}</math> | : <math> (\frac{MC 8}{North 8})_{500<Ephoton<600} = 0.0165 \frac{MeV}{Channel}</math> | ||
*'''Very Strange: Apparent Energy Dependence''' | *'''Very Strange: Apparent Energy Dependence''' | ||
| + | [[Image:Adccalib2.gif|480px]] | ||
| + | |||
| + | |||
| + | ;How do we see what's going on? | ||
| + | # Cuts: Trig==8 (MOR and BCal OR), Nphotons==1 | ||
| + | #*Possibly there are e+e-, maybe. Need to check the veto but it doesn't seem to be in the Root Trees | ||
| + | ## Cut out the lower hump from the ADC sum. | ||
| + | [[Image:AdcsumS 200to300.gif|thumb|left|100px|ADCsum South 200<Ephoton<300]] | ||
| + | [[Image:AdcsumS 300to400.gif|thumb|left|100px|ADCsum South 300<Ephoton<400]] | ||
| + | [[Image:AdcsumS 500to600.gif|thumb|none|100px|ADCsum South 500<Ephoton<600]] | ||
| + | <br> | ||
| + | This seems to remove the "junk" from the left of the spectra, and will flatten out the MC8/North8 ratio. But what is the "junk? | ||
| + | [[Image:North8 junk 300to400.gif|480px|left]] This has a 2% or more effect on the mean for 300<Ephoton<400. Probably much larger for the lower energies. | ||
Revision as of 19:33, 17 November 2006
First go
- Gain Correction:
- Establish the means of each cell in the Monte Carlo and find the ratio wrt MC Cell 8
- Find the current ratio of each ADC in the beamtest data wrt to North 8
- Correct the ADC ratio to match the Monte Carlo Ratios
- The ratio of MC Cell 8 to North 8 defines the MeV/Channel
- How does this look over the entire tagger spectrum?
- What if we look at MC 8 vs North 8 with Tagger Energy cuts?
- Very Strange: Apparent Energy Dependence
- How do we see what's going on?
- Cuts: Trig==8 (MOR and BCal OR), Nphotons==1
- Possibly there are e+e-, maybe. Need to check the veto but it doesn't seem to be in the Root Trees
- Cut out the lower hump from the ADC sum.
This seems to remove the "junk" from the left of the spectra, and will flatten out the MC8/North8 ratio. But what is the "junk?
