BCAL Beam Test Plots, November 20, 2006

First go

• Gain Correction:
  1. Establish the means of each cell in the Monte Carlo and find the ratio wrt MC Cell 8
  2. Find the current ratio of each ADC in the beamtest data wrt to North 8
  3. Correct the ADC ratio to match the Monte Carlo Ratios
     • The ratio of MC Cell 8 to North 8 defines the MeV/Channel

North 7

North 8

North 9

North 12

${\frac {MC8}{North8}}=0.018{\frac {MeV}{Channel}}$

How does this look over the entire tagger spectrum?

What if we look at MC 8 vs North 8 with Tagger Energy cuts?

North9 300<Ephoton<400

MC9 300<Ephoton<400

$({\frac {MC8}{North8}})_{{300<Ephoton<400}}=0.0177{\frac {MeV}{Channel}}$

North9 500<Ephoton<600

MC9 500<Ephoton<600

$({\frac {MC8}{North8}})_{{500<Ephoton<600}}=0.0165{\frac {MeV}{Channel}}$

• Very Strange: Apparent Energy Dependence