# Difference between revisions of "Mark's Sandbox"

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Assume line direction is chosen to go in the positive $y$ direction. If the line is parallel to the x-axis, choose the positive direction to be the positive x direction. Then angle of inclination of the line is an angle $\phi$, 0 <= phi < 180. Unit vector along the line is lhat = xhat cos phi + yhat sin phi, the unit vector normal to the line (in the detector plane) is nhat = -xhat sin phi + yhat cos phi. In this way, lhat and nhat satisfy the right hand rule, i. e., lhat cross nhat = zhat. | Assume line direction is chosen to go in the positive $y$ direction. If the line is parallel to the x-axis, choose the positive direction to be the positive x direction. Then angle of inclination of the line is an angle $\phi$, 0 <= phi < 180. Unit vector along the line is lhat = xhat cos phi + yhat sin phi, the unit vector normal to the line (in the detector plane) is nhat = -xhat sin phi + yhat cos phi. In this way, lhat and nhat satisfy the right hand rule, i. e., lhat cross nhat = zhat. | ||

− | [[test of wikitization of coding standards]] | + | * [[test of wikitization of coding standards]] |

− | [[Getting a Grid Certificate]] | + | * [[Getting a Grid Certificate]] |

* here are some new bullets | * here are some new bullets |

## Revision as of 15:07, 21 December 2012

random text forming a paragraph

Suggested coordinate system for linear detector elements in a plane perpendicular to z.

Assume line direction is chosen to go in the positive $y$ direction. If the line is parallel to the x-axis, choose the positive direction to be the positive x direction. Then angle of inclination of the line is an angle $\phi$, 0 <= phi < 180. Unit vector along the line is lhat = xhat cos phi + yhat sin phi, the unit vector normal to the line (in the detector plane) is nhat = -xhat sin phi + yhat cos phi. In this way, lhat and nhat satisfy the right hand rule, i. e., lhat cross nhat = zhat.

- here are some new bullets
- as a test

<img src="https://halldweb1.jlab.org/wiki/images/5/5b/D00000-01-01-2000.png">