Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
WE:Engineering (Energy and Utilities)
Re: (sqrt3 - sqrt2)^2
[#permalink]
04 Aug 2018, 18:25
Carcass wrote:
\((\sqrt3 - \sqrt2)^2\)
A. \(1 - 2 \sqrt{6}\)
B. \(1 - \sqrt{6}\)
C. \(5 - 2 \sqrt{6}\)
D. \(5 - 2 \sqrt{3}\)
E. \(1\)
Here
\((\sqrt3 - \sqrt2)^2 = (\sqrt3)^2 + (\sqrt2)^2 - 2 * (\sqrt3) * (\sqrt2) = 3 + 2 - 2\sqrt6 = 5 - 2 \sqrt{6}\)
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